'Weak Dependency Graph [60.0]' ------------------------------ Answer: YES(?,O(n^1)) Input Problem: innermost runtime-complexity with respect to Rules: { g(f(x), y) -> f(h(x, y)) , h(x, y) -> g(x, f(y))} Details: We have computed the following set of weak (innermost) dependency pairs: { g^#(f(x), y) -> c_0(h^#(x, y)) , h^#(x, y) -> c_1(g^#(x, f(y)))} The usable rules are: {} The estimated dependency graph contains the following edges: {g^#(f(x), y) -> c_0(h^#(x, y))} ==> {h^#(x, y) -> c_1(g^#(x, f(y)))} {h^#(x, y) -> c_1(g^#(x, f(y)))} ==> {g^#(f(x), y) -> c_0(h^#(x, y))} We consider the following path(s): 1) { g^#(f(x), y) -> c_0(h^#(x, y)) , h^#(x, y) -> c_1(g^#(x, f(y)))} The usable rules for this path are empty. We have oriented the usable rules with the following strongly linear interpretation: Interpretation Functions: g(x1, x2) = [0] x1 + [0] x2 + [0] f(x1) = [0] x1 + [0] h(x1, x2) = [0] x1 + [0] x2 + [0] g^#(x1, x2) = [0] x1 + [0] x2 + [0] c_0(x1) = [0] x1 + [0] h^#(x1, x2) = [0] x1 + [0] x2 + [0] c_1(x1) = [0] x1 + [0] We have applied the subprocessor on the resulting DP-problem: 'Weight Gap Principle' ---------------------- Answer: YES(?,O(n^1)) Input Problem: innermost DP runtime-complexity with respect to Strict Rules: { g^#(f(x), y) -> c_0(h^#(x, y)) , h^#(x, y) -> c_1(g^#(x, f(y)))} Weak Rules: {} Details: We apply the weight gap principle, strictly orienting the rules {h^#(x, y) -> c_1(g^#(x, f(y)))} and weakly orienting the rules {} using the following strongly linear interpretation: Processor 'Matrix Interpretation' oriented the following rules strictly: {h^#(x, y) -> c_1(g^#(x, f(y)))} Details: Interpretation Functions: g(x1, x2) = [0] x1 + [0] x2 + [0] f(x1) = [1] x1 + [0] h(x1, x2) = [0] x1 + [0] x2 + [0] g^#(x1, x2) = [1] x1 + [1] x2 + [1] c_0(x1) = [1] x1 + [1] h^#(x1, x2) = [1] x1 + [1] x2 + [8] c_1(x1) = [1] x1 + [0] Finally we apply the subprocessor 'fastest of 'combine', 'Bounds with default enrichment', 'Bounds with default enrichment'' ------------------------------------------------------------------------------------------ Answer: YES(?,O(n^1)) Input Problem: innermost DP runtime-complexity with respect to Strict Rules: {g^#(f(x), y) -> c_0(h^#(x, y))} Weak Rules: {h^#(x, y) -> c_1(g^#(x, f(y)))} Details: The problem was solved by processor 'combine': 'combine' --------- Answer: YES(?,O(n^1)) Input Problem: innermost DP runtime-complexity with respect to Strict Rules: {g^#(f(x), y) -> c_0(h^#(x, y))} Weak Rules: {h^#(x, y) -> c_1(g^#(x, f(y)))} Details: 'sequentially if-then-else, sequentially' ----------------------------------------- Answer: YES(?,O(n^1)) Input Problem: innermost DP runtime-complexity with respect to Strict Rules: {g^#(f(x), y) -> c_0(h^#(x, y))} Weak Rules: {h^#(x, y) -> c_1(g^#(x, f(y)))} Details: 'if Check whether the TRS is strict trs contains single rule then fastest else fastest' --------------------------------------------------------------------------------------- Answer: YES(?,O(n^1)) Input Problem: innermost DP runtime-complexity with respect to Strict Rules: {g^#(f(x), y) -> c_0(h^#(x, y))} Weak Rules: {h^#(x, y) -> c_1(g^#(x, f(y)))} Details: a) We first check the conditional [Success]: We are considering a strict trs contains single rule TRS. b) We continue with the then-branch: The problem was solved by processor 'fastest of 'Matrix Interpretation', 'Matrix Interpretation', 'Matrix Interpretation'': 'fastest of 'Matrix Interpretation', 'Matrix Interpretation', 'Matrix Interpretation'' -------------------------------------------------------------------------------------- Answer: YES(?,O(n^1)) Input Problem: innermost DP runtime-complexity with respect to Strict Rules: {g^#(f(x), y) -> c_0(h^#(x, y))} Weak Rules: {h^#(x, y) -> c_1(g^#(x, f(y)))} Details: The problem was solved by processor 'Matrix Interpretation': 'Matrix Interpretation' ----------------------- Answer: YES(?,O(n^1)) Input Problem: innermost DP runtime-complexity with respect to Strict Rules: {g^#(f(x), y) -> c_0(h^#(x, y))} Weak Rules: {h^#(x, y) -> c_1(g^#(x, f(y)))} Details: Interpretation Functions: g(x1, x2) = [0] x1 + [0] x2 + [0] f(x1) = [1] x1 + [6] h(x1, x2) = [0] x1 + [0] x2 + [0] g^#(x1, x2) = [3] x1 + [0] x2 + [0] c_0(x1) = [1] x1 + [2] h^#(x1, x2) = [3] x1 + [0] x2 + [1] c_1(x1) = [1] x1 + [1]